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-2x=3x^2-8
We move all terms to the left:
-2x-(3x^2-8)=0
We get rid of parentheses
-3x^2-2x+8=0
a = -3; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·(-3)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-3}=\frac{-8}{-6} =1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-3}=\frac{12}{-6} =-2 $
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